Coordination Compounds MCQ Questions for NEET
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In this article, we will share with you 20 MCQ questions from class 12 chemistry chapter 09 i.e. Coordination Compounds. Answer Key and detailed solutions of these questions is also given in this article so that there is no confusion left. Good Luck!
Questions
1. The IUPAC name of Na3[Co(ONO)6] is:
a) Sodium cobaltinitrite
b) Sodium hexanitritocobaltate(III)
c) Sodium hexanitrocobalt(III)
d) Sodium hexanitritocobaltate(II)
2. CuSO4 decolourises on addition of KCN, the product is:
a) Cu(CN)42-
b) [Cu(CN)4]3-
c) Cu(CN)2
d) CuCN
3. Exchange of coordination group by a water molecule in complex molecule results in:
a) Ionization isomerism
b) Ligand isomerism
c) Hydration isomerism
d) Geometrical isomerism
4. The type of isomerism found in urea molecule is
a) Chain
b) Position
c) Tautomerism
d) None of these
5. The IUPAC name of the compound is
a) Butane-2-aldehyde
b) 2-methyl butanal
c) 2-ethyl propanal
d) None of the above
6. Anisol is a product obtained from phenol by the reaction known as:
a) Coupling
b) Etherification
c) Oxidation
d) Esterification
7. Which of the following is diamagnetic in nature?
a) [Fe(CN)6]3-
b) [NiCl4]2-
c) [Ni(CO)4]
d) [MnCl4]2-
8. Which is the strongest field ligand?
a) CN-
b) NO2-
c) NH3
d) en
9. Nitrobenzene on reduction with Zn and aq. NH4Cl gives:
a) Aniline
b) Nitrosobenzene
c) N-phenyl hydroxylamine
d) Hydrazobenzene
10. The IUPAC name of [Co(NH3 )5ONO]2+ ion is
a) Pentaamminenitrito cobalt (IV) ion
b) Pentaammine nitro cobalt (III) ion
c) Pentaamminenitrito cobalt (III) ion
d) Pentaammine nitro cobalt (IV) ion
11. The compound which does not show paramagnetism is
a) NO2
b) NO
c) [Ag(NH3 )2 ]Cl
d) [Cu(NH3 )4 Cl2 ]
12. Which of the following is expected to undergo nitration more easily and readily to furnish the corresponding nitro derivatives employing the usual nitrating mixture?
a) C6H6
b) C6H5NO2
c) C6H5CH3
d) C6H5∙CCl3
13. The number of unpaired electrons calculated in [Co(NH3)6]3+ and [CoF6]3- are
a) 4 and 4
b) 0 and 2
c) 2 and 4
d) 0 and 4
14. The IUPAC name of
a) 4-hydroxy amino benzene carboxylic acid
b) 4-(N-hydroxy) imino benzene carboxylic acid
c) 4-hydroxy imino cyclohexanoic acid
d) 4-(N-hydroxy) imino cyclohexane-1-carboxylic acid
15. The IUPAC name of the coordination compound K2[Zn(OH)4] is
a) Potassium tetrahydroxozine (II)
b) Dipotassiumtetrahydroxo(II)
c) Potassium tetrahydroxozincate (II)
d) Potassium tetrahydroxozincate (III)
16. Arrange in order of decreasing trend towards SE reactions,
I. Chlorobenzene,
II. Benzene,
III. Anilium chloride,
IV. Toluene
a) II>I>III>IV
b) III>I>II>IV
c) IV>II<I>III
d) I>II>III>IV
17. Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so obtained is diazotised and then heated with cuprous bromide. The reaction mixture so formed contains:
a) Mixture of o- and m-bromotoluenes
b) Mixture of o- and p-bromotoluenes
c) Mixture of o- and p-dibromobenzenes
d) Mixture of o- and p-bromoanilines
18. A positive carbylamine test is given by:
a) N,N-dimethylaniline
b) 2,4-dimethylaniline
c) N-methyl-o-methylaniline
d) p-methyl benzylamine
19. CN- is strong field ligand. This is due to the fact that
a) It carries negative charge
b) It is a pseudohalide
c) It can accept electrons from metal species
d) It forms high spin complexes with metal species.
20. Which of the following is not true for ligand metal complex?
a) Highly charged ligand forms strong bond
b) Greater the ionization potential of central metal, the stronger is the bond
c) Larger the permanent dipole moment of ligand, the more stable is the bond
d) Larger the ligand, the more stable is the metal-ligand bond
Answer Key
| 1. b | 2. b | 3. c | 4. c | 5. b |
| 6. b | 7. c | 8. a | 9. c | 10. b |
| 11. c | 12. c | 13. d | 14. d | 15. c |
| 16. c | 17. b | 18. d | 19. b | 20. b |
Solutions
1 (b)
Follow IUPAC rules.
2 (b)
2CuSO4+10KCN ⟶2K3 Cu(CN)4+(CN)2+2K2 SO4
3 (c)
Follow definition of hydration isomerism.
4 (c)
Urea, NH2-CO-NH2; shows tautomerism as OH-NH2-C=NH
6 (b)
C6H5ONa + RX ⟶ C6H5OR (Anisole)
7 (c)
8 (a)
CN- is strongest field ligand. The spectrochemical series order is:
I-<Br-<Cl-<F-<[C2O4]2-<H2O<py <NH3<en<NO2-<CN-<CO
10 (b)
[Co(NH3)5ONO]2+
Penta ammine nitrito cobalt (III) ion.
11 (c)
In [Ag(NH3)2]Cl, Ag+ contains d10 configuration. As others contain unpaired electrons.
12 (c)
CH3 gp., an o-and p-directing group attached in nucleus activates the ring for SE reactions.
The presence of m-directing groups in benzene nucleous simply decreases electron density at o- and p-, whereas no change in electron density at m-position is noticed. 
On the contrary o-and p-directing groups in nucleus increases the electron density at o- and p-position.
Thus, presence of o- and p-directing groups provide seats for S_Ereactions or activates the ring, whereas presence of m-directing groups does not activate the ring and thus, deactivate the ring for S_E reactions
13 (d)
In both [Co(NH3 )6 ]3+ and [CoF6 ]3+,Co is present as Co3+.
Thus, the electronic configuration of Co is
27Co=[Ar] 3d7,4s2
27Co3+=[Ar]3d6,4s0
In case of [Co(NH3 )6 ]3+,NH3 is a strong field ligand, so pairing of electrons in 3d-orbital takes place.
27Co3+=[Ar]3d6,4s0
In [CoF6 ]3+,F is a weak field ligand, thus doesn’t cause pairing.
Hence,
27Co3+=[Ar]3d6,4s0
18 (d)
It is a test for primary amines. No doubt 2,4-dimethylaniline is also primary amine but it does not give test due to steric hindrance.
19 (b)
CN-is strong field ligand because it is an example of pseudohalide. Pseudohalide ions are stronger coordinating ligands and they have the ability to form σ bond and π-bond.
20 (b)
Higher the charge and smaller the size of ligand, more stable is the complex formed