Back to Top

Thermodynamics MCQ Questions for NEET

If you are preparing for NEET exam, this article will be a good help for you. This article contains mcq questions, answer keys and detailed solutions from class 11 chemistry chapter 6. Chemical Thermodynamics MCQs for NEET Exam. 

For chapter-wise MCQ questions, visit the following links: 

Questions

Q1. Standard enthalpy of vaporization ∆vap. H for water at 100℃ is 40.66 kJ mol-1. The internal energy of vapourisation of water at 100℃ (in kJ mol-1) is:
a) +43.76
b) +40.66
c) +37.56
d) -43.76

Q2. The factor (∂Q/∂T)P - (∂Q/∂T)V is equal to :
a) 𝛾
b) R
c) R/M
d) ∆nRT

Q3. Heat of combustion of a substance:
a) Is always positive
b) Is always negative
c) Is equal to heat of formation
d) Nothing can be said without reaction

Q4. The heat of formations of CO(g) and CO_2 (g) are -26.4 kcal and -94.0 kcal respectively. The heat of combustion of carbon monoxide will be
a) -67.6 kcal
b) 36.5 kcal
c) -36.5 kcal
d) -46.5 kcal

Q5. Which reaction either endothermic or exothermic characteristics has the greater chance of occurring spontaneously?
a) One in which entropy change is positive
b) One is which entropy change is negative
c) One in which Gibbs energy change is negative
d) One in which equilibrium has been established

Q6. Net work done by the system in a cyclic process is equal to:
a) Zero
b) ∆U
c) ∆H
d) q

Q7. A thermodynamic quantity is that:
a) Which is used in thermochemistry
b) Which obeys all the laws of thermodynamics
c) Quantity which depends only on the state of the system
d) Quantity which is used in measuring thermal change

Q8. The Gibbs energy change for a reversible reaction at equilibrium is:
a) Zero
b) Small positive
c) Small negative
d) Large positive

Q9. If, S + O2 → SO2; ∆H= -298.2 kJ ...(i)
SO2 + 1/2 O2 → SO3; ∆H= -98.7 kJ ...(ii)
SO3 + H2O → H2SO4; ∆H= -130.2 kJ ...(iii)
H2 + 1/2 O2 → H2O; ∆H= -227.3 kJ ...(iv)
The enthalpy of formation of H2SO4 at 298 K will be:
a) - 754.4 kJ
b) + 320.5 kJ
c) - 650.3 kJ
d) - 433.7 kJ

Q10. The heat required to raise the temperature of a body by 1 K is called
a) Specific heat
b) Thermal capacity
c) Water equivalent
d) None of these

Answer Key

1.c 2.b 3.b 4.a 5.c 6.d 7.c 8.a 9.a 10.b

Solutions

1 (c)
H2O(l) → H2O(v) ∴∆n=1
∆H°=∆U°+∆nRT
40.66×103=∆U°+1×8.314×373
∴∆U°=37559 J=37.56 kJ

2 (b)
(∂Q/∂T)P=Cp and (∂Q/∂T)V=Cv and Cp-Cv=R.

4 (a)
C(s) + 1/2 O2(g) → CO2 (g); ∆H1=-26.4
C(s) + 1/2 O2(g) → CO2 (g); ∆H2=-96.0
We have to find for ∆H, for reaction
CO + 1/2 O2 → CO2; ∆H1=?
Eqs. (ii) - (i), we get
∆H = -94 - (-26.4) = -67.6 k cal

5 (c)
If ∆G=-ve, process is spontaneous

6 (d)
∆U-W=q
If cyclic process, then q=-W.

7 (c)
e.g. U, H, S etc.

8 (a)
∆G=0 for an equilibrium state.

9 (a)
Find ∆H for, H2 + S + 2 O2 → H2SO4

We hope this article has been helpful. Thanks for visiting our website.